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This year marks my tenth year as a teacher of Maths. During that time, I've built up a bank of teaching resources and ideas which I want to share with others. Some can be incorporated into lessons and others act as discussion points.

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The majority of posts are focused around Maths, but there are some which look at pedagogy and CPD which can be used in other subjects/settings. Search for lesson resources using the tags at the side. Pedagogy has it's own section.

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Resources can be used in educational settings, including private tuition.

Percentage Change - Link Up

Percentages can be merged with a range of other topics. This worksheet has 22 questions that do just that, and there's fully worked solutions.

As a taster, here are two additional questions.

Solution

Let \(p\) be the number of purple sections, \(g\) be the number of green sections and \(n\) be the total number of sections. Now, \(P(orange\:or\:purple)=\frac{2+p}{n}\) and \(P(orange\:or\:green)=\frac{2+g}{n}\).

Use the percentage to form the equation \[\frac{2+p}{n}=1.05\left(\frac{2+g}{n}\right)\]\[2+p=1.05(2+g)\]\[20p=2+21g\]At this point, we can see that the LHS is a multiple of 20, so the RHS must be too. This means that \(21g\) must end in 8. Trial \(g=8\) and we get \(20p=170\) which is not an integer value for \(p\). Trialling \(g=18\) gives \(p=19\). So the minimum total number of sections is \(18+19+2=39\)

 


Solution

Let the radius be \(r\) then the area is \(\pi r^2\) and the circumference is \(2\pi r\). Set up an equation using the percentage.\[\pi r^2=1.92(2\pi r)\]\[r=3.84\]The diameter is therefore 7.68.

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