Triangulation seems to be the go-to approach when deriving the sum of interior angles, which feels intuitive given that we are looking at angles inside the polygon, but there are other ways, some of which might be easier to follow.
How might each of these be used to derive the sum of interior angles of a polygon?
Method 1 - Fan Triangulation
Drawing line segments from one vertex to all other vertices of an \(n\) sided polygon produces \(n-2\) triangles, each of which have angles that add up to 180 degrees. The sum of interior angles is therefore \(180(n-2)\).
Method 2 - Interior Point Triangulation
Drawing line segments from one point inside an \(n\) sided polygon to each of its vertices produces \(n\) triangles each of which have angles that sum to 180 degrees. The sum of the all these angles is \(180n\) but this includes the full turn at the point inside the polygon. Subtract 360 degrees to result in \(180n-360=180(n-2)\)
Method 3 - Summation of Interior and Exterior Angles
Each interior and exterior angle pair add up to 180 degrees. There are \(n\) angles so these add up to \(180n\). The sum of interior angles is this, minus the sum of exterior angles, which is always 360 degrees for a convex polygon. We then get \(180n-360=180(n-2)\) degrees, but without considering any triangulation.

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